##TITLE= Audit trail, TOPSPIN		Version 3.1
##JCAMPDX= 5.01
##ORIGIN= Bruker BioSpin GmbH
##OWNER= mfjofre
$$ /watusi/data/mfjofre/from_banyo2/nmr/cq_02867_100mM_2-6-2012/6/pdata/1/auditp.txt
##AUDIT TRAIL=  $$ (NUMBER, WHEN, WHO, WHERE, PROCESS, VERSION, WHAT)
(   1,<2012-02-07 19:30:29.776 -0600>,<mfjofre>,<kerry.nmrfam.wisc.edu>,<go>,<TOPSPIN 3.0>,
      <created by zg
	started at 2012-02-07 19:16:15.813 -0600,
	POWCHK enabled, PULCHK disabled,
       configuration hash MD5:
       CF 69 09 09 36 92 1C 20 BA 9E D1 74 A2 01 DC B8
       data hash MD5: 1K * 256
       53 59 DA 32 9B 46 38 E1 AD A1 FD 8C AA 4B 6B BA>)
(   2,<2012-02-15 12:22:37.894 -0600>,<mfjofre>,<watusi.nmrfam.wisc.edu>,<proc2d>,<TOPSPIN 3.1>,
      <Start of raw data processing
       xfb F2: SI = 1K WDW = 4 SSB = 2 FT_mod = 6 PKNL = 1 PHC0 = 0 PHC1 = 0 F1: SI = 1K ME_mod = 2 NCOEF = 32 WDW = 4 SSB = 2 FT_mod = 6
       data hash MD5: 1K * 1K
       22 81 80 F6 4F 35 00 D8 C5 55 DF 07 30 0B 3C 0A>)
(   3,<2012-02-15 12:23:01.064 -0600>,<mfjofre>,<watusi.nmrfam.wisc.edu>,<proc2d>,<TOPSPIN 3.1>,
      <pk2 fgphup F2: PHC0 = -56.75938 PHC1 = 0
       data hash MD5: 1K * 1K
       50 2D 67 DC 80 6B 07 31 A1 11 D2 DE 56 E7 BC 5C>)
(   4,<2012-02-15 12:23:23.292 -0600>,<mfjofre>,<watusi.nmrfam.wisc.edu>,<proc2d>,<TOPSPIN 3.1>,
      <pk1 fgphup F1: PHC0 = 17.26501 PHC1 = -24.275
       data hash MD5: 1K * 1K
       A0 94 D3 59 C2 5F 4C 25 69 5B 4F 82 B7 61 46 61>)
(   5,<2012-02-15 12:24:45.684 -0600>,<mfjofre>,<watusi.nmrfam.wisc.edu>,<proc2d>,<TOPSPIN 3.1>,
      <pk1 fgphup F1: PHC0 = -18.85901 PHC1 = 15.325
       data hash MD5: 1K * 1K
       8F EB 3D B3 92 29 66 AC E1 FB C6 92 09 A9 4A C1>)
(   6,<2012-02-15 12:25:18.284 -0600>,<mfjofre>,<watusi.nmrfam.wisc.edu>,<proc2d>,<TOPSPIN 3.1>,
      <pk1 fgphup F1: PHC0 = 31.93505 PHC1 = -58.8375
       data hash MD5: 1K * 1K
       A7 46 BD CA FE E5 36 36 BF 27 83 4E 72 23 C2 E3>)
(   7,<2012-02-15 12:26:03.664 -0600>,<mfjofre>,<watusi.nmrfam.wisc.edu>,<proc2d>,<TOPSPIN 3.1>,
      <pk1 fgphup F1: PHC0 = 9.89375 PHC1 = 0
       data hash MD5: 1K * 1K
       FD FC 6F D9 F0 DC 2F F5 7D 86 FD CE 55 E2 37 FE>)
(   8,<2012-02-15 12:26:40.231 -0600>,<mfjofre>,<watusi.nmrfam.wisc.edu>,<proc2d>,<TOPSPIN 3.1>,
      <pk1 fgphup F1: PHC0 = 5.124902 PHC1 = 6.1
       data hash MD5: 1K * 1K
       2A A4 76 1A CD DC E9 3B D2 43 FD 5C 20 24 CF A5>)
##END=

$$ hash MD5
$$ AB 20 B6 73 FD A3 A4 62 16 CF 13 5D 5F 79 49 48
